The four adjacent digits in the 1000–digit number that have the greatest product are 9 × 9 × 8 × 9 = 5832.
Find the greatest product of 13 adjacent digits in the 1000–digit number.
SolutionText with a dashed underscore will highlight the code section being talked about when moused over or tapped.
We begin by opening the file pe8.txt and concatenating its contents into one long string. Each line has all leading and trailing whitespace removed (e.g., \n, \t).
Next, each character is separated, converted to an integer digit, and then stored to a list named
d = [int(x) for x in ''.join(line.strip() for line in open('pe8.txt'))]
L defines the search length and must be at least equal to the length of
d. If not, we exit printing "None."
If there are enough digits then we consider all
L–digit subsets and store their product. The
for loop’s index,
i, is the starting index for the next set inside the string and the
reduce function multiplies each subset together.
Finally, we capture the maximum product for all the sets.
L = 13 print ('Greatest product of', L, 'consecutive \ndigits =', end='') print "None." if L>len(d) else \ max(reduce(mul, d[i:i+L]) for i in range(len(d)-L+1))
Easy mistakes to make
80% of the Python solutions listed in the Project Euler forum are wrong since they don’t consider the last digit in the search space. Because the solution to this problem lies somewhere in the middle, these programs calculate a correct response in this instance. However, if you were to run them with the following parameters they would fail by erroneously producing a zero instead of 18:
d = [0,0,0,1,9,2];
L = 3
Further, many of these same programs would crash with an error or erroneously return zero when the search length exceeds the string length. It’s better to return some indication that an answer cannot be calculated, such as "None." Here’s an example for an undefined condition:
d = [0,0,0,1,9,2];
L = 13
HackerRank steps up the complexity by running up to 100 test cases and changing the search length from a fixed 13 digits to a variable 1 through 7 digits. The search object can range from 1 to 1000 digits.
Python Source Code
from functools import reduce from operator import mul d = [int(x) for x in ''.join(line.strip() for line in open('pe8.txt'))] dL = len(d) L = int(input('Enter a set length (0 > L > '+str(dL)+')? ')) print ('Greatest product of', L, 'consecutive digits = ', end='') print ("None." if L>dL else \ max(reduce(mul, d[i:i+L]) for i in range(dL-L+1)))
- The data file, pe8.txt, is available on repl.it page by clicking the files icon in the top left corner.
- The backslash ('\') at the end of line 8 continues the program statement to the next line to improve readability.
- You might consider the effect of 0's and 1's in the string on the product, but it was ignored for this solution.